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On what basis does the final conclusion in irrationality of (\sqrt{3}) come?
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Answer and explanation
Correct answer: Rational assumption makes both (p) and (q) divisible by (3)
Both being divisible by (3) breaks the coprime condition. Therefore (\sqrt{3}) cannot be rational.
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What is the correct answer to this question?
Rational assumption makes both (p) and (q) divisible by (3)
Why is this the correct answer?
Both being divisible by (3) breaks the coprime condition. Therefore (\sqrt{3}) cannot be rational.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Proof of irrationality of square root 2 and square root 3.
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