संख्या रेखा पर (x) ऐसा है कि (-1<x<0) और \(x^2=\frac{1}{9}\)। (x) कौन-सा है?

On the number line, (x) satisfies (-1<x<0) and \(x^2=\frac{1}{9}\). What is (x)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(-\frac{1}{3}\)

Step 1

Concept

From \(x^2=\frac{1}{9}\), \(x=\pm\frac{1}{3}\), and the given interval needs the negative value. In exams, use conditions to choose the correct sign.

Step 2

Why this answer is correct

The correct answer is B. \(-\frac{1}{3}\). From \(x^2=\frac{1}{9}\), \(x=\pm\frac{1}{3}\), and the given interval needs the negative value. In exams, use conditions to choose the correct sign.

Step 3

Exam Tip

\(x^2=\frac{1}{9}\) से \(x=\pm\frac{1}{3}\), और दिए गए अंतराल में ऋणात्मक मान चाहिए। परीक्षा में शर्तों से सही चिह्न चुनें।

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संख्या रेखा पर (x) ऐसा है कि (-1<x<0) और \(x^2=\frac{1}{9}\)। (x) कौन-सा है? / On the number line, (x) satisfies (-1<x<0) and \(x^2=\frac{1}{9}\). What is (x)?

Correct Answer: B. \(-\frac{1}{3}\). Explanation: \(x^2=\frac{1}{9}\) से \(x=\pm\frac{1}{3}\), और दिए गए अंतराल में ऋणात्मक मान चाहिए। परीक्षा में शर्तों से सही चिह्न चुनें। / From \(x^2=\frac{1}{9}\), \(x=\pm\frac{1}{3}\), and the given interval needs the negative value. In exams, use conditions to choose the correct sign.

Which concept should I revise for this Mathematics MCQ?

From \(x^2=\frac{1}{9}\), \(x=\pm\frac{1}{3}\), and the given interval needs the negative value. In exams, use conditions to choose the correct sign.

What exam hint can help solve this Mathematics question?

\(x^2=\frac{1}{9}\) से \(x=\pm\frac{1}{3}\), और दिए गए अंतराल में ऋणात्मक मान चाहिए। परीक्षा में शर्तों से सही चिह्न चुनें।