संख्या रेखा पर (x) ऐसा है कि (-1<x<0) और \(x^2=\frac{1}{9}\)। (x) कौन-सा है?
On the number line, (x) satisfies (-1<x<0) and \(x^2=\frac{1}{9}\). What is (x)?
Explanation opens after your attempt
B. \(-\frac{1}{3}\)
Concept
From \(x^2=\frac{1}{9}\), \(x=\pm\frac{1}{3}\), and the given interval needs the negative value. In exams, use conditions to choose the correct sign.
Why this answer is correct
The correct answer is B. \(-\frac{1}{3}\). From \(x^2=\frac{1}{9}\), \(x=\pm\frac{1}{3}\), and the given interval needs the negative value. In exams, use conditions to choose the correct sign.
Exam Tip
\(x^2=\frac{1}{9}\) से \(x=\pm\frac{1}{3}\), और दिए गए अंतराल में ऋणात्मक मान चाहिए। परीक्षा में शर्तों से सही चिह्न चुनें।
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