व्यंजक \(x^2+\frac{x}{3}-4\) बहुपद है या नहीं?

Is \(x^2+\frac{x}{3}-4\) a polynomial or not?

Explanation opens after your attempt
Correct Answer

A. हां, क्योंकि \(\frac{x}{3}\) में (x) की घात (1) हैYes, because in \(\frac{x}{3}\), the power of (x) is (1)

Step 1

Concept

The coefficient of \(\frac{x}{3}\) is \(\frac{1}{3}\), and the power is (1). Therefore it is a polynomial.

Step 2

Why this answer is correct

The correct answer is A. हां, क्योंकि \(\frac{x}{3}\) में (x) की घात (1) है / Yes, because in \(\frac{x}{3}\), the power of (x) is (1). The coefficient of \(\frac{x}{3}\) is \(\frac{1}{3}\), and the power is (1). Therefore it is a polynomial.

Step 3

Exam Tip

\(\frac{x}{3}\) का गुणांक \(\frac{1}{3}\) है और घात (1) है। इसलिए यह बहुपद है।

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Mathematics Answer, Explanation and Revision Hints

व्यंजक \(x^2+\frac{x}{3}-4\) बहुपद है या नहीं? / Is \(x^2+\frac{x}{3}-4\) a polynomial or not?

Correct Answer: A. हां, क्योंकि \(\frac{x}{3}\) में (x) की घात (1) है / Yes, because in \(\frac{x}{3}\), the power of (x) is (1). Explanation: \(\frac{x}{3}\) का गुणांक \(\frac{1}{3}\) है और घात (1) है। इसलिए यह बहुपद है। / The coefficient of \(\frac{x}{3}\) is \(\frac{1}{3}\), and the power is (1). Therefore it is a polynomial.

Which concept should I revise for this Mathematics MCQ?

The coefficient of \(\frac{x}{3}\) is \(\frac{1}{3}\), and the power is (1). Therefore it is a polynomial.

What exam hint can help solve this Mathematics question?

\(\frac{x}{3}\) का गुणांक \(\frac{1}{3}\) है और घात (1) है। इसलिए यह बहुपद है।