किस विकल्प में व्यंजक बहुपद नहीं है लेकिन सभी गुणांक वास्तविक हैं?

In which option is the expression not a polynomial although all coefficients are real?

Explanation opens after your attempt
Correct Answer

D. \(6x^{-2}+8\)

Step 1

Concept

Having real coefficients is not enough. Because of the negative power \(x^{-2}\), it is not a polynomial.

Step 2

Why this answer is correct

The correct answer is D. \(6x^{-2}+8\). Having real coefficients is not enough. Because of the negative power \(x^{-2}\), it is not a polynomial.

Step 3

Exam Tip

वास्तविक गुणांक होना पर्याप्त नहीं है। \(x^{-2}\) की ऋणात्मक घात के कारण यह बहुपद नहीं है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

किस विकल्प में व्यंजक बहुपद नहीं है लेकिन सभी गुणांक वास्तविक हैं? / In which option is the expression not a polynomial although all coefficients are real?

Correct Answer: D. \(6x^{-2}+8\). Explanation: वास्तविक गुणांक होना पर्याप्त नहीं है। \(x^{-2}\) की ऋणात्मक घात के कारण यह बहुपद नहीं है। / Having real coefficients is not enough. Because of the negative power \(x^{-2}\), it is not a polynomial.

Which concept should I revise for this Mathematics MCQ?

Having real coefficients is not enough. Because of the negative power \(x^{-2}\), it is not a polynomial.

What exam hint can help solve this Mathematics question?

वास्तविक गुणांक होना पर्याप्त नहीं है। \(x^{-2}\) की ऋणात्मक घात के कारण यह बहुपद नहीं है।