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In which option do all terms have valid powers of the variable for a polynomial?

Answer and explanation

Correct answer: \(x^2+x+1\)

In a polynomial, the exponent of a variable must be a non-negative integer: 0, 1, 2, 3, and so on. In \(x^2+x+1\), the powers of \(x\) are 2, 1, and 0, so it is a polynomial. Options B and D have negative exponents, while option C has \(\sqrt{x}=x^{1/2}\), a fractional exponent; hence they are not polynomials. Exam tip: reject an expression as a polynomial if a variable has a negative or fractional exponent.

Related tags

PolynomialsDefinition Of PolynomialNon-Negative Integer ExponentsAlgebraClass 9 MathematicsDefinition Of A PolynomialIntroduction To PolynomialsMathematics

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