\(\sqrt{2}\) के प्रमाण में \(m^2=2n^2\) से सीधे (n) सम लिखना क्यों अधूरा है?

In the proof of \(\sqrt{2}\), why is it incomplete to write directly from \(m^2=2n^2\) that (n) is even?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. पहले (m) सम सिद्ध करके (m=2r) रखना पड़ता हैFirst (m) must be proved even and (m=2r) must be used

Step 1

Concept

From \(m^2=2n^2\), (m) is proved even first. Only after putting (m=2r), \(n^2=2r^2\) is obtained.

Step 2

Why this answer is correct

The correct answer is A. पहले (m) सम सिद्ध करके (m=2r) रखना पड़ता है / First (m) must be proved even and (m=2r) must be used. From \(m^2=2n^2\), (m) is proved even first. Only after putting (m=2r), \(n^2=2r^2\) is obtained.

Step 3

Exam Tip

\(m^2=2n^2\) से पहले (m) सम मिलता है। (m=2r) रखने पर ही \(n^2=2r^2\) बनता है।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{2}\) के प्रमाण में \(m^2=2n^2\) से सीधे (n) सम लिखना क्यों अधूरा है? / In the proof of \(\sqrt{2}\), why is it incomplete to write directly from \(m^2=2n^2\) that (n) is even?

Correct Answer: A. पहले (m) सम सिद्ध करके (m=2r) रखना पड़ता है / First (m) must be proved even and (m=2r) must be used. Explanation: \(m^2=2n^2\) से पहले (m) सम मिलता है। (m=2r) रखने पर ही \(n^2=2r^2\) बनता है। / From \(m^2=2n^2\), (m) is proved even first. Only after putting (m=2r), \(n^2=2r^2\) is obtained.

Which concept should I revise for this Mathematics MCQ?

From \(m^2=2n^2\), (m) is proved even first. Only after putting (m=2r), \(n^2=2r^2\) is obtained.

What exam hint can help solve this Mathematics question?

\(m^2=2n^2\) से पहले (m) सम मिलता है। (m=2r) रखने पर ही \(n^2=2r^2\) बनता है।