गुणोत्तर श्रेणी \(512,256,128,\ldots\) में (4) कौन-सा पद है?

In the geometric progression \(512,256,128,\ldots\), which term is (4)?

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Correct Answer

B. आठवाँ पद(8)th term

Step 1

Concept

From (512\left\(\frac{1}{2}\right\)^{n-1}=4), (\left\(\frac{1}{2}\right\)^{n-1}=\frac{1}{128}), so (n=8). In exams count terms while halving.

Step 2

Why this answer is correct

The correct answer is B. आठवाँ पद / (8)th term. From (512\left\(\frac{1}{2}\right\)^{n-1}=4), (\left\(\frac{1}{2}\right\)^{n-1}=\frac{1}{128}), so (n=8). In exams count terms while halving.

Step 3

Exam Tip

(512\left\(\frac{1}{2}\right\)^{n-1}=4) से (\left\(\frac{1}{2}\right\)^{n-1}=\frac{1}{128}) इसलिए (n=8) है। परीक्षा में आधा करते हुए पद गिनें।

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Mathematics Answer, Explanation and Revision Hints

गुणोत्तर श्रेणी \(512,256,128,\ldots\) में (4) कौन-सा पद है? / In the geometric progression \(512,256,128,\ldots\), which term is (4)?

Correct Answer: B. आठवाँ पद / (8)th term. Explanation: (512\left\(\frac{1}{2}\right\)^{n-1}=4) से (\left\(\frac{1}{2}\right\)^{n-1}=\frac{1}{128}) इसलिए (n=8) है। परीक्षा में आधा करते हुए पद गिनें। / From (512\left\(\frac{1}{2}\right\)^{n-1}=4), (\left\(\frac{1}{2}\right\)^{n-1}=\frac{1}{128}), so (n=8). In exams count terms while halving.

Which concept should I revise for this Mathematics MCQ?

From (512\left\(\frac{1}{2}\right\)^{n-1}=4), (\left\(\frac{1}{2}\right\)^{n-1}=\frac{1}{128}), so (n=8). In exams count terms while halving.

What exam hint can help solve this Mathematics question?

(512\left\(\frac{1}{2}\right\)^{n-1}=4) से (\left\(\frac{1}{2}\right\)^{n-1}=\frac{1}{128}) इसलिए (n=8) है। परीक्षा में आधा करते हुए पद गिनें।