समांतर श्रेणी \(6,10,14,\ldots\) में (50) से पहले आने वाला अंतिम पद कौन-सा है?

In the arithmetic progression \(6,10,14,\ldots\), what is the last term before (50)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (46)

Step 1

Concept

The general term is \(a_n=4n+2\), and the greatest term below (50) is (46). In boundary questions check nearby terms.

Step 2

Why this answer is correct

The correct answer is C. (46). The general term is \(a_n=4n+2\), and the greatest term below (50) is (46). In boundary questions check nearby terms.

Step 3

Exam Tip

सामान्य पद \(a_n=4n+2\) है और (50) से छोटा सबसे बड़ा पद (46) है। सीमा वाले प्रश्न में नजदीकी पद जांचें।

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Mathematics Answer, Explanation and Revision Hints

समांतर श्रेणी \(6,10,14,\ldots\) में (50) से पहले आने वाला अंतिम पद कौन-सा है? / In the arithmetic progression \(6,10,14,\ldots\), what is the last term before (50)?

Correct Answer: C. (46). Explanation: सामान्य पद \(a_n=4n+2\) है और (50) से छोटा सबसे बड़ा पद (46) है। सीमा वाले प्रश्न में नजदीकी पद जांचें। / The general term is \(a_n=4n+2\), and the greatest term below (50) is (46). In boundary questions check nearby terms.

Which concept should I revise for this Mathematics MCQ?

The general term is \(a_n=4n+2\), and the greatest term below (50) is (46). In boundary questions check nearby terms.

What exam hint can help solve this Mathematics question?

सामान्य पद \(a_n=4n+2\) है और (50) से छोटा सबसे बड़ा पद (46) है। सीमा वाले प्रश्न में नजदीकी पद जांचें।