सरल रूप में \( \frac{99}{363} \) का दशमलव प्रसार कैसा होगा?

In simplest form, what type of decimal expansion will \( \frac{99}{363} \) have?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. असांत आवर्तीNon-terminating recurring

Step 1

Concept

\( \frac{99}{363}=\frac{3}{11} \), and the denominator has (11). So the decimal will be non-terminating recurring.

Step 2

Why this answer is correct

The correct answer is C. असांत आवर्ती / Non-terminating recurring. \( \frac{99}{363}=\frac{3}{11} \), and the denominator has (11). So the decimal will be non-terminating recurring.

Step 3

Exam Tip

\( \frac{99}{363}=\frac{3}{11} \) है और हर में (11) है। इसलिए दशमलव असांत आवर्ती होगा।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

सरल रूप में \( \frac{99}{363} \) का दशमलव प्रसार कैसा होगा? / In simplest form, what type of decimal expansion will \( \frac{99}{363} \) have?

Correct Answer: C. असांत आवर्ती / Non-terminating recurring. Explanation: \( \frac{99}{363}=\frac{3}{11} \) है और हर में (11) है। इसलिए दशमलव असांत आवर्ती होगा। / \( \frac{99}{363}=\frac{3}{11} \), and the denominator has (11). So the decimal will be non-terminating recurring.

Which concept should I revise for this Mathematics MCQ?

\( \frac{99}{363}=\frac{3}{11} \), and the denominator has (11). So the decimal will be non-terminating recurring.

What exam hint can help solve this Mathematics question?

\( \frac{99}{363}=\frac{3}{11} \) है और हर में (11) है। इसलिए दशमलव असांत आवर्ती होगा।