वर्गमूल सर्पिल में \(\sqrt{2}\) की लंबाई किस प्रकार की संख्या है?
In a square root spiral, what type of number is the length \(\sqrt{2}\)?
Explanation opens after your attempt
Correct Answer
A. अपरिमेय संख्याIrrational number
Concept
\(\sqrt{2}\) is not the square root of a perfect square. Therefore it is irrational.
Why this answer is correct
The correct answer is A. अपरिमेय संख्या / Irrational number. \(\sqrt{2}\) is not the square root of a perfect square. Therefore it is irrational.
Exam Tip
\(\sqrt{2}\) पूर्ण वर्ग का वर्गमूल नहीं है। इसलिए यह अपरिमेय संख्या है।
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