वर्गमूल सर्पिल में यदि \(\sqrt{n}\) के बाद बना कर्ण पूर्ण संख्या (20) है, तो (n) का मान क्या था?

In a square root spiral, if the hypotenuse formed after \(\sqrt{n}\) is the whole number (20), what was the value of (n)?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

A. (399)

Step 1

Concept

The new hypotenuse is \(20=\sqrt{400}\). Therefore (n+1=400), so (n=399).

Step 2

Why this answer is correct

The correct answer is A. (399). The new hypotenuse is \(20=\sqrt{400}\). Therefore (n+1=400), so (n=399).

Step 3

Exam Tip

नया कर्ण \(20=\sqrt{400}\) है। इसलिए (n+1=400), अतः (n=399)।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में यदि \(\sqrt{n}\) के बाद बना कर्ण पूर्ण संख्या (20) है, तो (n) का मान क्या था? / In a square root spiral, if the hypotenuse formed after \(\sqrt{n}\) is the whole number (20), what was the value of (n)?

Correct Answer: A. (399). Explanation: नया कर्ण \(20=\sqrt{400}\) है। इसलिए (n+1=400), अतः (n=399)। / The new hypotenuse is \(20=\sqrt{400}\). Therefore (n+1=400), so (n=399).

Which concept should I revise for this Mathematics MCQ?

The new hypotenuse is \(20=\sqrt{400}\). Therefore (n+1=400), so (n=399).

What exam hint can help solve this Mathematics question?

नया कर्ण \(20=\sqrt{400}\) है। इसलिए (n+1=400), अतः (n=399)।