वर्गमूल सर्पिल में यदि \(\sqrt{n}\) कर्ण पर (1) इकाई लंब बनाई जाती है, तो कौन-सा कथन गलत है?
In a square root spiral, if a (1) unit perpendicular is drawn on hypotenuse \(\sqrt{n}\), which statement is incorrect?
Explanation opens after your attempt
Correct Answer
D. नया कर्ण \(\sqrt{n}+1\) होगाThe new hypotenuse will be \(\sqrt{n}+1\)
Concept
The new hypotenuse is not directly \(\sqrt{n}+1\). It is (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}).
Why this answer is correct
The correct answer is D. नया कर्ण \(\sqrt{n}+1\) होगा / The new hypotenuse will be \(\sqrt{n}+1\). The new hypotenuse is not directly \(\sqrt{n}+1\). It is (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}).
Exam Tip
नया कर्ण सीधे \(\sqrt{n}+1\) नहीं होता। वह (\sqrt{\(\sqrt{n}\)2+12}=\sqrt{n+1}) होता है।
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