यदि \(z=\sqrt{19}-\sqrt{10}\) है तो \(z^2\) का मान कौन-सा है?
If \(z=\sqrt{19}-\sqrt{10}\), which is the value of \(z^2\)?
Explanation opens after your attempt
C. \(29-2\sqrt{190}\)
Concept
(\(\sqrt{19}-\sqrt{10}\)2=19+10-2\sqrt{190}). Keep the middle term negative.
Why this answer is correct
The correct answer is C. \(29-2\sqrt{190}\). (\(\sqrt{19}-\sqrt{10}\)2=19+10-2\sqrt{190}). Keep the middle term negative.
Exam Tip
(\(\sqrt{19}-\sqrt{10}\)2=19+10-2\sqrt{190}) है। मध्य पद का चिन्ह ऋणात्मक रखें।
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