यदि \(x=\sqrt{9+\sqrt{7}}\) है तो \(x^2-9\) का मान क्या है?
If \(x=\sqrt{9+\sqrt{7}}\), what is the value of \(x^2-9\)?
Explanation opens after your attempt
A. \(\sqrt{7}\)
Concept
\(x^2=9+\sqrt{7}\). Therefore \(x^2-9=\sqrt{7}\).
Why this answer is correct
The correct answer is A. \(\sqrt{7}\). \(x^2=9+\sqrt{7}\). Therefore \(x^2-9=\sqrt{7}\).
Exam Tip
\(x^2=9+\sqrt{7}\) है। इसलिए \(x^2-9=\sqrt{7}\) होगा।
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