यदि \(x=\sqrt{2}+\sqrt{8}\) और \(y=\sqrt{18}\) हैं तो (x-y) का मान क्या है?
If \(x=\sqrt{2}+\sqrt{8}\) and \(y=\sqrt{18}\), what is the value of (x-y)?
Explanation opens after your attempt
Correct Answer
A. (0)
Concept
\(x=\sqrt{2}+2\sqrt{2}=3\sqrt{2}\) and \(y=3\sqrt{2}\). Therefore (x-y=0).
Why this answer is correct
The correct answer is A. (0). \(x=\sqrt{2}+2\sqrt{2}=3\sqrt{2}\) and \(y=3\sqrt{2}\). Therefore (x-y=0).
Exam Tip
\(x=\sqrt{2}+2\sqrt{2}=3\sqrt{2}\) और \(y=3\sqrt{2}\) है। इसलिए (x-y=0) है।
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