यदि \(x=\sqrt{10}+\sqrt{6}\) है, तो \(x^2-16\) का मान क्या है?
If \(x=\sqrt{10}+\sqrt{6}\), what is the value of \(x^2-16\)?
Explanation opens after your attempt
Correct Answer
B. \(4\sqrt{15}\)
Concept
\(x^2=10+6+2\sqrt{60}=16+4\sqrt{15}\). So \(x^2-16=4\sqrt{15}\).
Why this answer is correct
The correct answer is B. \(4\sqrt{15}\). \(x^2=10+6+2\sqrt{60}=16+4\sqrt{15}\). So \(x^2-16=4\sqrt{15}\).
Exam Tip
\(x^2=10+6+2\sqrt{60}=16+4\sqrt{15}\) है। इसलिए \(x^2-16=4\sqrt{15}\) है।
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