यदि \(x=\sqrt{10}-\sqrt{2}\) है तो \(x^2\) का मान कौन-सा है?

If \(x=\sqrt{10}-\sqrt{2}\), which is the value of \(x^2\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(12-4\sqrt{5}\)

Step 1

Concept

(\(\sqrt{10}-\sqrt{2}\)2=10+2-2\sqrt{20}=12-4\sqrt{5}). Watch the sign of the middle term.

Step 2

Why this answer is correct

The correct answer is A. \(12-4\sqrt{5}\). (\(\sqrt{10}-\sqrt{2}\)2=10+2-2\sqrt{20}=12-4\sqrt{5}). Watch the sign of the middle term.

Step 3

Exam Tip

(\(\sqrt{10}-\sqrt{2}\)2=10+2-2\sqrt{20}=12-4\sqrt{5}) है। मध्य पद का चिन्ह ध्यान रखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=\sqrt{10}-\sqrt{2}\) है तो \(x^2\) का मान कौन-सा है? / If \(x=\sqrt{10}-\sqrt{2}\), which is the value of \(x^2\)?

Correct Answer: A. \(12-4\sqrt{5}\). Explanation: (\(\sqrt{10}-\sqrt{2}\)2=10+2-2\sqrt{20}=12-4\sqrt{5}) है। मध्य पद का चिन्ह ध्यान रखें। / (\(\sqrt{10}-\sqrt{2}\)2=10+2-2\sqrt{20}=12-4\sqrt{5}). Watch the sign of the middle term.

Which concept should I revise for this Mathematics MCQ?

(\(\sqrt{10}-\sqrt{2}\)2=10+2-2\sqrt{20}=12-4\sqrt{5}). Watch the sign of the middle term.

What exam hint can help solve this Mathematics question?

(\(\sqrt{10}-\sqrt{2}\)2=10+2-2\sqrt{20}=12-4\sqrt{5}) है। मध्य पद का चिन्ह ध्यान रखें।