यदि \(x=5+\sqrt{24}\) है, तो \(x^2-10x\) का मान क्या है?
If \(x=5+\sqrt{24}\), what is the value of \(x^2-10x\)?
Explanation opens after your attempt
A. (-1)
Concept
\(x^2=49+10\sqrt{24}\) and \(10x=50+10\sqrt{24}\). Subtracting gives (-1).
Why this answer is correct
The correct answer is A. (-1). \(x^2=49+10\sqrt{24}\) and \(10x=50+10\sqrt{24}\). Subtracting gives (-1).
Exam Tip
\(x^2=49+10\sqrt{24}\) और \(10x=50+10\sqrt{24}\) है। घटाने पर (-1) मिलता है।
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