यदि \(x=5+\sqrt{24}\) है, तो \(x^2-10x\) का मान क्या है?

If \(x=5+\sqrt{24}\), what is the value of \(x^2-10x\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (-1)

Step 1

Concept

\(x^2=49+10\sqrt{24}\) and \(10x=50+10\sqrt{24}\). Subtracting gives (-1).

Step 2

Why this answer is correct

The correct answer is A. (-1). \(x^2=49+10\sqrt{24}\) and \(10x=50+10\sqrt{24}\). Subtracting gives (-1).

Step 3

Exam Tip

\(x^2=49+10\sqrt{24}\) और \(10x=50+10\sqrt{24}\) है। घटाने पर (-1) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=5+\sqrt{24}\) है, तो \(x^2-10x\) का मान क्या है? / If \(x=5+\sqrt{24}\), what is the value of \(x^2-10x\)?

Correct Answer: A. (-1). Explanation: \(x^2=49+10\sqrt{24}\) और \(10x=50+10\sqrt{24}\) है। घटाने पर (-1) मिलता है। / \(x^2=49+10\sqrt{24}\) and \(10x=50+10\sqrt{24}\). Subtracting gives (-1).

Which concept should I revise for this Mathematics MCQ?

\(x^2=49+10\sqrt{24}\) and \(10x=50+10\sqrt{24}\). Subtracting gives (-1).

What exam hint can help solve this Mathematics question?

\(x^2=49+10\sqrt{24}\) और \(10x=50+10\sqrt{24}\) है। घटाने पर (-1) मिलता है।