यदि \(x=5+\sqrt{2}\) है तो (x-5) किस प्रकार की संख्या है?

If \(x=5+\sqrt{2}\), what type of number is (x-5)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. अपरिमेयIrrational

Step 1

Concept

\(x-5=\sqrt{2}\), which is irrational. First remove rational terms and simplify.

Step 2

Why this answer is correct

The correct answer is C. अपरिमेय / Irrational. \(x-5=\sqrt{2}\), which is irrational. First remove rational terms and simplify.

Step 3

Exam Tip

\(x-5=\sqrt{2}\) है जो अपरिमेय है। पहले परिमेय पदों को हटाकर सरल करें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(x=5+\sqrt{2}\) है तो (x-5) किस प्रकार की संख्या है? / If \(x=5+\sqrt{2}\), what type of number is (x-5)?

Correct Answer: C. अपरिमेय / Irrational. Explanation: \(x-5=\sqrt{2}\) है जो अपरिमेय है। पहले परिमेय पदों को हटाकर सरल करें। / \(x-5=\sqrt{2}\), which is irrational. First remove rational terms and simplify.

Which concept should I revise for this Mathematics MCQ?

\(x-5=\sqrt{2}\), which is irrational. First remove rational terms and simplify.

What exam hint can help solve this Mathematics question?

\(x-5=\sqrt{2}\) है जो अपरिमेय है। पहले परिमेय पदों को हटाकर सरल करें।