यदि \(w=\sqrt{13}+\sqrt{6}\) है तो \(w^2-19\) का मान क्या है?
If \(w=\sqrt{13}+\sqrt{6}\), what is the value of \(w^2-19\)?
Explanation opens after your attempt
Correct Answer
B. \(2\sqrt{78}\)
Concept
\(w^2=13+6+2\sqrt{78}=19+2\sqrt{78}\). So \(w^2-19=2\sqrt{78}\).
Why this answer is correct
The correct answer is B. \(2\sqrt{78}\). \(w^2=13+6+2\sqrt{78}=19+2\sqrt{78}\). So \(w^2-19=2\sqrt{78}\).
Exam Tip
\(w^2=13+6+2\sqrt{78}=19+2\sqrt{78}\) है। इसलिए \(w^2-19=2\sqrt{78}\) है।
Login to save your score, XP, coins and progress.