यदि समांतर श्रेणी के लगातार तीन पद (3x-2), (4x+3), (6x+1) हैं, तो समान अंतर क्या है?
If three consecutive terms of an arithmetic progression are (3x-2), (4x+3), (6x+1), what is the common difference?
Explanation opens after your attempt
D. (12)
Concept
From (2(4x+3)=(3x-2)+(6x+1)), (x=7), so the terms are (19,31,43) and the difference is (12). First find (x), then find the difference.
Why this answer is correct
The correct answer is D. (12). From (2(4x+3)=(3x-2)+(6x+1)), (x=7), so the terms are (19,31,43) and the difference is (12). First find (x), then find the difference.
Exam Tip
(2(4x+3)=(3x-2)+(6x+1)) से (x=7), इसलिए पद (19,31,43) और अंतर (12) है। पहले (x) निकालें फिर अंतर निकालें।
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