यदि समांतर श्रेणी के लगातार तीन पद (3x-2), (4x+3), (6x+1) हैं, तो समान अंतर क्या है?

If three consecutive terms of an arithmetic progression are (3x-2), (4x+3), (6x+1), what is the common difference?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

D. (12)

Step 1

Concept

From (2(4x+3)=(3x-2)+(6x+1)), (x=7), so the terms are (19,31,43) and the difference is (12). First find (x), then find the difference.

Step 2

Why this answer is correct

The correct answer is D. (12). From (2(4x+3)=(3x-2)+(6x+1)), (x=7), so the terms are (19,31,43) and the difference is (12). First find (x), then find the difference.

Step 3

Exam Tip

(2(4x+3)=(3x-2)+(6x+1)) से (x=7), इसलिए पद (19,31,43) और अंतर (12) है। पहले (x) निकालें फिर अंतर निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि समांतर श्रेणी के लगातार तीन पद (3x-2), (4x+3), (6x+1) हैं, तो समान अंतर क्या है? / If three consecutive terms of an arithmetic progression are (3x-2), (4x+3), (6x+1), what is the common difference?

Correct Answer: D. (12). Explanation: (2(4x+3)=(3x-2)+(6x+1)) से (x=7), इसलिए पद (19,31,43) और अंतर (12) है। पहले (x) निकालें फिर अंतर निकालें। / From (2(4x+3)=(3x-2)+(6x+1)), (x=7), so the terms are (19,31,43) and the difference is (12). First find (x), then find the difference.

Which concept should I revise for this Mathematics MCQ?

From (2(4x+3)=(3x-2)+(6x+1)), (x=7), so the terms are (19,31,43) and the difference is (12). First find (x), then find the difference.

What exam hint can help solve this Mathematics question?

(2(4x+3)=(3x-2)+(6x+1)) से (x=7), इसलिए पद (19,31,43) और अंतर (12) है। पहले (x) निकालें फिर अंतर निकालें।