यदि वर्गमूल सर्पिल में \(\sqrt{24}\) कर्ण बन चुका है, तो अगला कर्ण किस गणना से मिलेगा?

If the hypotenuse \(\sqrt{24}\) has been constructed in a square root spiral, by which calculation will the next hypotenuse be obtained?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \(\sqrt{24+1}\)

Step 1

Concept

At every new step \(1^2\) is added. Therefore \(\sqrt{25}\) comes after \(\sqrt{24}\).

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{24+1}\). At every new step \(1^2\) is added. Therefore \(\sqrt{25}\) comes after \(\sqrt{24}\).

Step 3

Exam Tip

हर नए चरण में \(1^2\) जुड़ता है। इसलिए \(\sqrt{24}\) के बाद \(\sqrt{25}\) मिलता है।

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यदि वर्गमूल सर्पिल में \(\sqrt{24}\) कर्ण बन चुका है, तो अगला कर्ण किस गणना से मिलेगा? / If the hypotenuse \(\sqrt{24}\) has been constructed in a square root spiral, by which calculation will the next hypotenuse be obtained?

Correct Answer: C. \(\sqrt{24+1}\). Explanation: हर नए चरण में \(1^2\) जुड़ता है। इसलिए \(\sqrt{24}\) के बाद \(\sqrt{25}\) मिलता है। / At every new step \(1^2\) is added. Therefore \(\sqrt{25}\) comes after \(\sqrt{24}\).

Which concept should I revise for this Mathematics MCQ?

At every new step \(1^2\) is added. Therefore \(\sqrt{25}\) comes after \(\sqrt{24}\).

What exam hint can help solve this Mathematics question?

हर नए चरण में \(1^2\) जुड़ता है। इसलिए \(\sqrt{24}\) के बाद \(\sqrt{25}\) मिलता है।