यदि \(t\neq0\), तो \(tx^{16}+0x^{18}+7x^9-6\) की डिग्री क्या है?
If \(t\neq0\), what is the degree of \(tx^{16}+0x^{18}+7x^9-6\)?
Explanation opens after your attempt
B. (16)
Concept
\(0x^{18}\) is a zero term, and \(t\neq0\) keeps the \(x^{16}\) term. Therefore the degree is (16).
Why this answer is correct
The correct answer is B. (16). \(0x^{18}\) is a zero term, and \(t\neq0\) keeps the \(x^{16}\) term. Therefore the degree is (16).
Exam Tip
\(0x^{18}\) शून्य पद है और \(t\neq0\) से \(x^{16}\) पद बचता है। इसलिए डिग्री (16) है।
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