यदि \(t\neq0\), तो \(tx^{15}+0x^{17}+6x^8-5\) की डिग्री क्या है?
If \(t\neq0\), what is the degree of \(tx^{15}+0x^{17}+6x^8-5\)?
Explanation opens after your attempt
B. (15)
Concept
\(0x^{17}\) is a zero term, and \(t\neq0\) keeps the \(x^{15}\) term. Therefore the degree is (15).
Why this answer is correct
The correct answer is B. (15). \(0x^{17}\) is a zero term, and \(t\neq0\) keeps the \(x^{15}\) term. Therefore the degree is (15).
Exam Tip
\(0x^{17}\) शून्य पद है और \(t\neq0\) से \(x^{15}\) पद बचता है। इसलिए डिग्री (15) है।
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