यदि (q(x)=(c+5)x-3+(c-2)x-2+4x-1) की घात (2) करनी हो, तो कौन-सी शर्त चाहिए?
If (q(x)=(c+5)x-3+(c-2)x-2+4x-1) must have degree (2), what condition is needed?
Explanation opens after your attempt
C. (c=-5)
Concept
For degree (2), the coefficient of \(x^3\) must be zero. From (c+5=0), (c=-5), and the \(x^2\) coefficient (-7) remains non-zero.
Why this answer is correct
The correct answer is C. (c=-5). For degree (2), the coefficient of \(x^3\) must be zero. From (c+5=0), (c=-5), and the \(x^2\) coefficient (-7) remains non-zero.
Exam Tip
घात (2) के लिए \(x^3\) का गुणांक शून्य होना चाहिए। (c+5=0) से (c=-5) और \(x^2\) का गुणांक (-7) अशून्य रहता है।
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