यदि (p(x)=\lambda x-2+4x-3) की घात (2) है, तो \(\lambda\) के लिए सही शर्त क्या है?
If (p(x)=\lambda x-2+4x-3) has degree (2), what is the correct condition for \(\lambda\)?
Explanation opens after your attempt
B. \(\lambda\neq0\)
Concept
The degree will be (2) only if the coefficient of \(x^2\) is non-zero. Therefore, \(\lambda\neq0\) is required.
Why this answer is correct
The correct answer is B. \(\lambda\neq0\). The degree will be (2) only if the coefficient of \(x^2\) is non-zero. Therefore, \(\lambda\neq0\) is required.
Exam Tip
घात (2) तभी होगी जब \(x^2\) का गुणांक शून्य न हो। इसलिए \(\lambda\neq0\) चाहिए।
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