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If (p^2=3q^2) and (p=3k), what combined conclusion about (p) and (q) follows from (q^2=3k^2)?

Answer and explanation

Correct answer: Both are divisible by 3

From p = 3k, p is divisible by 3. Also, q² = 3k² shows that q² is divisible by 3. Since 3 is prime, if it divides the square of an integer, it must divide that integer itself. Hence q is also divisible by 3. Therefore, both p and q are divisible by 3. Option A has no basis because divisibility by 2 is not implied. Exam tip: In contradiction proofs of irrationality, showing that two assumed coprime integers share a prime factor produces the contradiction.

Related tags

Number SystemsIrrationality ProofSquare Root Of 3Prime DivisibilityContradiction ProofProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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