यदि \(\frac{a}{b}\) सरलतम रूप में है और (a) तथा (b) दोनों सम मिलते हैं तो क्या निष्कर्ष है?

If \(\frac{a}{b}\) is in lowest form and both (a) and (b) are found even, what is the conclusion?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. यह असंभव है क्योंकि (2) सामान्य गुणनखंड हैThis is impossible because (2) is a common factor

Step 1

Concept

In lowest form, numerator and denominator should be coprime. Both even is a contradiction.

Step 2

Why this answer is correct

The correct answer is A. यह असंभव है क्योंकि (2) सामान्य गुणनखंड है / This is impossible because (2) is a common factor. In lowest form, numerator and denominator should be coprime. Both even is a contradiction.

Step 3

Exam Tip

सरलतम रूप में अंश और हर सहभाज्य होने चाहिए। दोनों सम मिलना विरोधाभास है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\frac{a}{b}\) सरलतम रूप में है और (a) तथा (b) दोनों सम मिलते हैं तो क्या निष्कर्ष है? / If \(\frac{a}{b}\) is in lowest form and both (a) and (b) are found even, what is the conclusion?

Correct Answer: A. यह असंभव है क्योंकि (2) सामान्य गुणनखंड है / This is impossible because (2) is a common factor. Explanation: सरलतम रूप में अंश और हर सहभाज्य होने चाहिए। दोनों सम मिलना विरोधाभास है। / In lowest form, numerator and denominator should be coprime. Both even is a contradiction.

Which concept should I revise for this Mathematics MCQ?

In lowest form, numerator and denominator should be coprime. Both even is a contradiction.

What exam hint can help solve this Mathematics question?

सरलतम रूप में अंश और हर सहभाज्य होने चाहिए। दोनों सम मिलना विरोधाभास है।