यदि \(c=\sqrt{6}+\sqrt{2}\) और \(d=\sqrt{6}-\sqrt{2}\) हैं, तो (cd) और (c-d) का सही युग्म कौन-सा है?

If \(c=\sqrt{6}+\sqrt{2}\) and \(d=\sqrt{6}-\sqrt{2}\), which is the correct pair of (cd) and (c-d)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (4), \(2\sqrt{2}\)

Step 1

Concept

(cd=6-2=4) and \(c-d=2\sqrt{2}\). In conjugate forms find the product and difference separately.

Step 2

Why this answer is correct

The correct answer is A. (4), \(2\sqrt{2}\). (cd=6-2=4) and \(c-d=2\sqrt{2}\). In conjugate forms find the product and difference separately.

Step 3

Exam Tip

(cd=6-2=4) और \(c-d=2\sqrt{2}\) है। संयुग्मी रूप में गुणन और अंतर अलग-अलग निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(c=\sqrt{6}+\sqrt{2}\) और \(d=\sqrt{6}-\sqrt{2}\) हैं, तो (cd) और (c-d) का सही युग्म कौन-सा है? / If \(c=\sqrt{6}+\sqrt{2}\) and \(d=\sqrt{6}-\sqrt{2}\), which is the correct pair of (cd) and (c-d)?

Correct Answer: A. (4), \(2\sqrt{2}\). Explanation: (cd=6-2=4) और \(c-d=2\sqrt{2}\) है। संयुग्मी रूप में गुणन और अंतर अलग-अलग निकालें। / (cd=6-2=4) and \(c-d=2\sqrt{2}\). In conjugate forms find the product and difference separately.

Which concept should I revise for this Mathematics MCQ?

(cd=6-2=4) and \(c-d=2\sqrt{2}\). In conjugate forms find the product and difference separately.

What exam hint can help solve this Mathematics question?

(cd=6-2=4) और \(c-d=2\sqrt{2}\) है। संयुग्मी रूप में गुणन और अंतर अलग-अलग निकालें।