यदि \(\sqrt{2}\) परिमेय मानने पर विरोधाभास मिलता है तो यह किस मान्यता को गलत सिद्ध करता है?

If assuming \(\sqrt{2}\) rational gives a contradiction, which assumption does it prove false?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. \(\sqrt{2}\) परिमेय है\(\sqrt{2}\) is rational

Step 1

Concept

The contradiction rejects only the rationality assumption. Therefore \(\sqrt{2}\) is proved irrational.

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{2}\) परिमेय है / \(\sqrt{2}\) is rational. The contradiction rejects only the rationality assumption. Therefore \(\sqrt{2}\) is proved irrational.

Step 3

Exam Tip

विरोधाभास केवल परिमेय मान्यता को अस्वीकार करता है। इसलिए \(\sqrt{2}\) अपरिमेय सिद्ध होता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(\sqrt{2}\) परिमेय मानने पर विरोधाभास मिलता है तो यह किस मान्यता को गलत सिद्ध करता है? / If assuming \(\sqrt{2}\) rational gives a contradiction, which assumption does it prove false?

Correct Answer: C. \(\sqrt{2}\) परिमेय है / \(\sqrt{2}\) is rational. Explanation: विरोधाभास केवल परिमेय मान्यता को अस्वीकार करता है। इसलिए \(\sqrt{2}\) अपरिमेय सिद्ध होता है। / The contradiction rejects only the rationality assumption. Therefore \(\sqrt{2}\) is proved irrational.

Which concept should I revise for this Mathematics MCQ?

The contradiction rejects only the rationality assumption. Therefore \(\sqrt{2}\) is proved irrational.

What exam hint can help solve this Mathematics question?

विरोधाभास केवल परिमेय मान्यता को अस्वीकार करता है। इसलिए \(\sqrt{2}\) अपरिमेय सिद्ध होता है।