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If assuming √2 is rational gives a contradiction, which assumption is proved false?

Answer and explanation

Correct answer: √2 is rational

A proof by contradiction begins by temporarily assuming the statement opposite to the desired conclusion. To prove that √2 is irrational, we assume that √2 is rational and write it as p/q in lowest form. The algebra and divisibility arguments then force both p and q to be divisible by 2, contradicting their coprimality. The contradiction therefore rejects the temporary assumption that √2 is rational. It does not reject the facts that √2 is real, positive, or greater than zero; those facts remain true. Hence option C is correct. Options A, B, and D describe valid properties of √2 and are not the assumption targeted by the contradiction.

Related tags

Number-SystemsSqrt2Proof-By-ContradictionProof Of Irrationality Of Square Root 2 And Square Root 3Number SystemsMathematicsClass 9 Mcq

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