यदि \(A=\sqrt{98}+\sqrt{162}\) और \(B=16\sqrt{2}\) हैं तो कौन-सा कथन सही है?
If \(A=\sqrt{98}+\sqrt{162}\) and \(B=16\sqrt{2}\), which statement is correct?
Explanation opens after your attempt
Correct Answer
C. (A=B)
Concept
\(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{162}=9\sqrt{2}\), so \(A=16\sqrt{2}\). Hence (A=B).
Why this answer is correct
The correct answer is C. (A=B). \(\sqrt{98}=7\sqrt{2}\) and \(\sqrt{162}=9\sqrt{2}\), so \(A=16\sqrt{2}\). Hence (A=B).
Exam Tip
\(\sqrt{98}=7\sqrt{2}\) और \(\sqrt{162}=9\sqrt{2}\), इसलिए \(A=16\sqrt{2}\) है। अतः (A=B) है।
Login to save your score, XP, coins and progress.