यदि \(a_n=405\left(\frac{1}{3}\right)^{n-1}\) है, तो कौन-सा पद (5) के बराबर होगा?
If \(a_n=405\left(\frac{1}{3}\right)^{n-1}\), which term will be equal to (5)?
Explanation opens after your attempt
C. पाँचवाँ पद(5)th term
Concept
From \(405\left(\frac{1}{3}\right)^{n-1}=5\), \(\left(\frac{1}{3}\right)^{n-1}=\frac{1}{81}\), so (n=5). In exams, simplify fractions first.
Why this answer is correct
The correct answer is C. पाँचवाँ पद / (5)th term. From \(405\left(\frac{1}{3}\right)^{n-1}=5\), \(\left(\frac{1}{3}\right)^{n-1}=\frac{1}{81}\), so (n=5). In exams, simplify fractions first.
Exam Tip
\(405\left(\frac{1}{3}\right)^{n-1}=5\) से \(\left(\frac{1}{3}\right)^{n-1}=\frac{1}{81}\), इसलिए (n=5) है। परीक्षा में भिन्नों को पहले सरल करें।
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