यदि \(a_n=100\left(\frac{1}{2}\right)^{n-1}\) है तो कौन-सा पद \(\frac{25}{2}\) के बराबर होगा?
If \(a_n=100\left(\frac{1}{2}\right)^{n-1}\), which term will be equal to \(\frac{25}{2}\)?
Explanation opens after your attempt
Correct Answer
B. चौथा पद(4)th term
Concept
From \(100\left(\frac{1}{2}\right)^{n-1}=\frac{25}{2}\), \(\left(\frac{1}{2}\right)^{n-1}=\frac{1}{8}\), so (n=4). In exams simplify fractions first.
Why this answer is correct
The correct answer is B. चौथा पद / (4)th term. From \(100\left(\frac{1}{2}\right)^{n-1}=\frac{25}{2}\), \(\left(\frac{1}{2}\right)^{n-1}=\frac{1}{8}\), so (n=4). In exams simplify fractions first.
Exam Tip
\(100\left(\frac{1}{2}\right)^{n-1}=\frac{25}{2}\) से \(\left(\frac{1}{2}\right)^{n-1}=\frac{1}{8}\) इसलिए (n=4) है। परीक्षा में भिन्नों को पहले सरल करें।
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