यदि \(a=5+\sqrt{6}\) और \(b=5-\sqrt{6}\) हैं तो \(a^2-b^2\) का मान क्या है?
If \(a=5+\sqrt{6}\) and \(b=5-\sqrt{6}\), what is the value of \(a^2-b^2\)?
Explanation opens after your attempt
Correct Answer
C. \(20\sqrt{6}\)
Concept
(a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{6}\) and (a+b=10). So the value is \(20\sqrt{6}\).
Why this answer is correct
The correct answer is C. \(20\sqrt{6}\). (a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{6}\) and (a+b=10). So the value is \(20\sqrt{6}\).
Exam Tip
(a-2-b-2=(a-b)(a+b)) है जहाँ \(a-b=2\sqrt{6}\) और (a+b=10) है। इसलिए मान \(20\sqrt{6}\) है।
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