यदि \(a=4+\sqrt{2}\) और \(b=4-\sqrt{2}\) हैं, तो \(a^2-b^2\) का मान क्या है?
If \(a=4+\sqrt{2}\) and \(b=4-\sqrt{2}\), what is the value of \(a^2-b^2\)?
Explanation opens after your attempt
A. \(16\sqrt{2}\)
Concept
(a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{2}\) and (a+b=8). So the value is \(16\sqrt{2}\).
Why this answer is correct
The correct answer is A. \(16\sqrt{2}\). (a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{2}\) and (a+b=8). So the value is \(16\sqrt{2}\).
Exam Tip
(a-2-b-2=(a-b)(a+b)) है जहाँ \(a-b=2\sqrt{2}\) और (a+b=8) है। इसलिए मान \(16\sqrt{2}\) है।
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