यदि \(a=4+\sqrt{2}\) और \(b=4-\sqrt{2}\) हैं, तो \(a^2-b^2\) का मान क्या है?

If \(a=4+\sqrt{2}\) and \(b=4-\sqrt{2}\), what is the value of \(a^2-b^2\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(16\sqrt{2}\)

Step 1

Concept

(a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{2}\) and (a+b=8). So the value is \(16\sqrt{2}\).

Step 2

Why this answer is correct

The correct answer is A. \(16\sqrt{2}\). (a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{2}\) and (a+b=8). So the value is \(16\sqrt{2}\).

Step 3

Exam Tip

(a-2-b-2=(a-b)(a+b)) है जहाँ \(a-b=2\sqrt{2}\) और (a+b=8) है। इसलिए मान \(16\sqrt{2}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a=4+\sqrt{2}\) और \(b=4-\sqrt{2}\) हैं, तो \(a^2-b^2\) का मान क्या है? / If \(a=4+\sqrt{2}\) and \(b=4-\sqrt{2}\), what is the value of \(a^2-b^2\)?

Correct Answer: A. \(16\sqrt{2}\). Explanation: (a-2-b-2=(a-b)(a+b)) है जहाँ \(a-b=2\sqrt{2}\) और (a+b=8) है। इसलिए मान \(16\sqrt{2}\) है। / (a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{2}\) and (a+b=8). So the value is \(16\sqrt{2}\).

Which concept should I revise for this Mathematics MCQ?

(a-2-b-2=(a-b)(a+b)) where \(a-b=2\sqrt{2}\) and (a+b=8). So the value is \(16\sqrt{2}\).

What exam hint can help solve this Mathematics question?

(a-2-b-2=(a-b)(a+b)) है जहाँ \(a-b=2\sqrt{2}\) और (a+b=8) है। इसलिए मान \(16\sqrt{2}\) है।