यदि \(a=3\sqrt{2}+4\) और \(b=3\sqrt{2}-4\) हैं तो (a+b) क्या है?

If \(a=3\sqrt{2}+4\) and \(b=3\sqrt{2}-4\), what is (a+b)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(6\sqrt{2}\)

Step 1

Concept

The constant terms cancel and \(3\sqrt{2}+3\sqrt{2}=6\sqrt{2}\). Add like radicals.

Step 2

Why this answer is correct

The correct answer is B. \(6\sqrt{2}\). The constant terms cancel and \(3\sqrt{2}+3\sqrt{2}=6\sqrt{2}\). Add like radicals.

Step 3

Exam Tip

स्थिर पद कट जाते हैं और \(3\sqrt{2}+3\sqrt{2}=6\sqrt{2}\) मिलता है। समान मूलों को जोड़ें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a=3\sqrt{2}+4\) और \(b=3\sqrt{2}-4\) हैं तो (a+b) क्या है? / If \(a=3\sqrt{2}+4\) and \(b=3\sqrt{2}-4\), what is (a+b)?

Correct Answer: B. \(6\sqrt{2}\). Explanation: स्थिर पद कट जाते हैं और \(3\sqrt{2}+3\sqrt{2}=6\sqrt{2}\) मिलता है। समान मूलों को जोड़ें। / The constant terms cancel and \(3\sqrt{2}+3\sqrt{2}=6\sqrt{2}\). Add like radicals.

Which concept should I revise for this Mathematics MCQ?

The constant terms cancel and \(3\sqrt{2}+3\sqrt{2}=6\sqrt{2}\). Add like radicals.

What exam hint can help solve this Mathematics question?

स्थिर पद कट जाते हैं और \(3\sqrt{2}+3\sqrt{2}=6\sqrt{2}\) मिलता है। समान मूलों को जोड़ें।