वर्गमूल सर्पिल में यदि \(\sqrt{14}\) कर्ण पर (1) इकाई लंब बनती है, तो नया कर्ण किस अंतराल में आएगा?
If a (1) unit perpendicular is drawn on hypotenuse \(\sqrt{14}\) in a square root spiral, in which interval will the new hypotenuse lie?
Explanation opens after your attempt
B. (3) और (4) के बीचBetween (3) and (4)
Concept
The new hypotenuse will be \(\sqrt{15}\). Since \(3^2<15<4^2\), it lies between (3) and (4).
Why this answer is correct
The correct answer is B. (3) और (4) के बीच / Between (3) and (4). The new hypotenuse will be \(\sqrt{15}\). Since \(3^2<15<4^2\), it lies between (3) and (4).
Exam Tip
नया कर्ण \(\sqrt{15}\) होगा। क्योंकि \(3^2<15<4^2\), यह (3) और (4) के बीच है।
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