वर्गमूल सर्पिल में यदि \(\sqrt{14}\) कर्ण पर (1) इकाई लंब बनती है, तो नया कर्ण किस अंतराल में आएगा?

If a (1) unit perpendicular is drawn on hypotenuse \(\sqrt{14}\) in a square root spiral, in which interval will the new hypotenuse lie?

Author: Muft Shiksha Editorial Team Published: Updated:
Explanation opens after your attempt
Correct Answer

B. (3) और (4) के बीचBetween (3) and (4)

Step 1

Concept

The new hypotenuse will be \(\sqrt{15}\). Since \(3^2<15<4^2\), it lies between (3) and (4).

Step 2

Why this answer is correct

The correct answer is B. (3) और (4) के बीच / Between (3) and (4). The new hypotenuse will be \(\sqrt{15}\). Since \(3^2<15<4^2\), it lies between (3) and (4).

Step 3

Exam Tip

नया कर्ण \(\sqrt{15}\) होगा। क्योंकि \(3^2<15<4^2\), यह (3) और (4) के बीच है।

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वर्गमूल सर्पिल में यदि \(\sqrt{14}\) कर्ण पर (1) इकाई लंब बनती है, तो नया कर्ण किस अंतराल में आएगा? / If a (1) unit perpendicular is drawn on hypotenuse \(\sqrt{14}\) in a square root spiral, in which interval will the new hypotenuse lie?

Correct Answer: B. (3) और (4) के बीच / Between (3) and (4). Explanation: नया कर्ण \(\sqrt{15}\) होगा। क्योंकि \(3^2<15<4^2\), यह (3) और (4) के बीच है। / The new hypotenuse will be \(\sqrt{15}\). Since \(3^2<15<4^2\), it lies between (3) and (4).

Which concept should I revise for this Mathematics MCQ?

The new hypotenuse will be \(\sqrt{15}\). Since \(3^2<15<4^2\), it lies between (3) and (4).

What exam hint can help solve this Mathematics question?

नया कर्ण \(\sqrt{15}\) होगा। क्योंकि \(3^2<15<4^2\), यह (3) और (4) के बीच है।