यदि \(a_1=8\) और \(a_{n+1}=\frac{a_n}{2}+a_1\) है तो \(a_4\) क्या होगा?

If \(a_1=8\) and \(a_{n+1}=\frac{a_n}{2}+a_1\), what is \(a_4\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (15)

Step 1

Concept

The terms are (8,12,14,15), so \(a_4=15\). Exam tip: \(a_1\) stays fixed and half of the previous term is used.

Step 2

Why this answer is correct

The correct answer is C. (15). The terms are (8,12,14,15), so \(a_4=15\). Exam tip: \(a_1\) stays fixed and half of the previous term is used.

Step 3

Exam Tip

पद (8,12,14,15) हैं इसलिए \(a_4=15\) है। \(a_1\) स्थिर रहता है और पिछले पद का आधा लिया जाता है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=8\) और \(a_{n+1}=\frac{a_n}{2}+a_1\) है तो \(a_4\) क्या होगा? / If \(a_1=8\) and \(a_{n+1}=\frac{a_n}{2}+a_1\), what is \(a_4\)?

Correct Answer: C. (15). Explanation: पद (8,12,14,15) हैं इसलिए \(a_4=15\) है। \(a_1\) स्थिर रहता है और पिछले पद का आधा लिया जाता है। / The terms are (8,12,14,15), so \(a_4=15\). Exam tip: \(a_1\) stays fixed and half of the previous term is used.

Which concept should I revise for this Mathematics MCQ?

The terms are (8,12,14,15), so \(a_4=15\). Exam tip: \(a_1\) stays fixed and half of the previous term is used.

What exam hint can help solve this Mathematics question?

पद (8,12,14,15) हैं इसलिए \(a_4=15\) है। \(a_1\) स्थिर रहता है और पिछले पद का आधा लिया जाता है।