यदि \(a_1=64\) और \(a_{n+1}=\frac{a_n}{2}+n^2\) है तो \(a_3\) क्या होगा?

If \(a_1=64\) and \(a_{n+1}=\frac{a_n}{2}+n^2\), what is \(a_3\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(\frac{41}{2}\)

Step 1

Concept

\(a_2=32+1=33\) and \(a_3=\frac{33}{2}+4=\frac{41}{2}\). Exam tip: keep fractions exact until the end.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{41}{2}\). \(a_2=32+1=33\) and \(a_3=\frac{33}{2}+4=\frac{41}{2}\). Exam tip: keep fractions exact until the end.

Step 3

Exam Tip

\(a_2=32+1=33\) और \(a_3=\frac{33}{2}+4=\frac{41}{2}\) है। भिन्न को अंत तक सही रखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=64\) और \(a_{n+1}=\frac{a_n}{2}+n^2\) है तो \(a_3\) क्या होगा? / If \(a_1=64\) and \(a_{n+1}=\frac{a_n}{2}+n^2\), what is \(a_3\)?

Correct Answer: B. \(\frac{41}{2}\). Explanation: \(a_2=32+1=33\) और \(a_3=\frac{33}{2}+4=\frac{41}{2}\) है। भिन्न को अंत तक सही रखें। / \(a_2=32+1=33\) and \(a_3=\frac{33}{2}+4=\frac{41}{2}\). Exam tip: keep fractions exact until the end.

Which concept should I revise for this Mathematics MCQ?

\(a_2=32+1=33\) and \(a_3=\frac{33}{2}+4=\frac{41}{2}\). Exam tip: keep fractions exact until the end.

What exam hint can help solve this Mathematics question?

\(a_2=32+1=33\) और \(a_3=\frac{33}{2}+4=\frac{41}{2}\) है। भिन्न को अंत तक सही रखें।