यदि \(a_1=6\) और (a_{n+1}=a_n+(-1)^n(2n)) है तो \(a_5\) क्या होगा?

If \(a_1=6\) and (a_{n+1}=a_n+(-1)^n(2n)), what is \(a_5\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (6)

Step 1

Concept

The terms are (6,4,8,2,10), so \(a_5=10\). Exam tip: check even and odd (n) in sign-changing rules.

Step 2

Why this answer is correct

The correct answer is C. (6). The terms are (6,4,8,2,10), so \(a_5=10\). Exam tip: check even and odd (n) in sign-changing rules.

Step 3

Exam Tip

पद (6,4,8,2,10) नहीं बल्कि \(a_5=10\) है। चिह्न बदलने वाले पदों में सम-विषम (n) जाँचें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=6\) और (a_{n+1}=a_n+(-1)^n(2n)) है तो \(a_5\) क्या होगा? / If \(a_1=6\) and (a_{n+1}=a_n+(-1)^n(2n)), what is \(a_5\)?

Correct Answer: C. (6). Explanation: पद (6,4,8,2,10) नहीं बल्कि \(a_5=10\) है। चिह्न बदलने वाले पदों में सम-विषम (n) जाँचें। / The terms are (6,4,8,2,10), so \(a_5=10\). Exam tip: check even and odd (n) in sign-changing rules.

Which concept should I revise for this Mathematics MCQ?

The terms are (6,4,8,2,10), so \(a_5=10\). Exam tip: check even and odd (n) in sign-changing rules.

What exam hint can help solve this Mathematics question?

पद (6,4,8,2,10) नहीं बल्कि \(a_5=10\) है। चिह्न बदलने वाले पदों में सम-विषम (n) जाँचें।