यदि \(a_1=5\) और \(a_{n+1}=a_n+\frac{3n}{2}\) है तो \(a_5\) क्या होगा?

If \(a_1=5\) and \(a_{n+1}=a_n+\frac{3n}{2}\), what is \(a_5\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (20)

Step 1

Concept

The total addition is (\frac{3(1+2+3+4)}{2}=15), so \(a_5=20\). Exam tip: find the total fractional addition first.

Step 2

Why this answer is correct

The correct answer is C. (20). The total addition is (\frac{3(1+2+3+4)}{2}=15), so \(a_5=20\). Exam tip: find the total fractional addition first.

Step 3

Exam Tip

कुल जोड़ (\frac{3(1+2+3+4)}{2}=15) है इसलिए \(a_5=20\) है। भिन्न जोड़ में पहले कुल जोड़ निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=5\) और \(a_{n+1}=a_n+\frac{3n}{2}\) है तो \(a_5\) क्या होगा? / If \(a_1=5\) and \(a_{n+1}=a_n+\frac{3n}{2}\), what is \(a_5\)?

Correct Answer: C. (20). Explanation: कुल जोड़ (\frac{3(1+2+3+4)}{2}=15) है इसलिए \(a_5=20\) है। भिन्न जोड़ में पहले कुल जोड़ निकालें। / The total addition is (\frac{3(1+2+3+4)}{2}=15), so \(a_5=20\). Exam tip: find the total fractional addition first.

Which concept should I revise for this Mathematics MCQ?

The total addition is (\frac{3(1+2+3+4)}{2}=15), so \(a_5=20\). Exam tip: find the total fractional addition first.

What exam hint can help solve this Mathematics question?

कुल जोड़ (\frac{3(1+2+3+4)}{2}=15) है इसलिए \(a_5=20\) है। भिन्न जोड़ में पहले कुल जोड़ निकालें।