यदि \(a_1=4\) और \(a_{n+1}=a_n+\frac{a_n}{4}+n\) है तो \(a_3\) क्या होगा?

If \(a_1=4\) and \(a_{n+1}=a_n+\frac{a_n}{4}+n\), what is \(a_3\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\frac{19}{2}\)

Step 1

Concept

\(a_2=4+1+1=6\) and \(a_3=6+\frac{6}{4}+2=\frac{19}{2}\). Exam tip: keep fractions exact until the end.

Step 2

Why this answer is correct

The correct answer is B. \(\frac{19}{2}\). \(a_2=4+1+1=6\) and \(a_3=6+\frac{6}{4}+2=\frac{19}{2}\). Exam tip: keep fractions exact until the end.

Step 3

Exam Tip

\(a_2=4+1+1=6\) और \(a_3=6+\frac{6}{4}+2=\frac{19}{2}\) है। भिन्नों को अंत तक ठीक रखें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=4\) और \(a_{n+1}=a_n+\frac{a_n}{4}+n\) है तो \(a_3\) क्या होगा? / If \(a_1=4\) and \(a_{n+1}=a_n+\frac{a_n}{4}+n\), what is \(a_3\)?

Correct Answer: B. \(\frac{19}{2}\). Explanation: \(a_2=4+1+1=6\) और \(a_3=6+\frac{6}{4}+2=\frac{19}{2}\) है। भिन्नों को अंत तक ठीक रखें। / \(a_2=4+1+1=6\) and \(a_3=6+\frac{6}{4}+2=\frac{19}{2}\). Exam tip: keep fractions exact until the end.

Which concept should I revise for this Mathematics MCQ?

\(a_2=4+1+1=6\) and \(a_3=6+\frac{6}{4}+2=\frac{19}{2}\). Exam tip: keep fractions exact until the end.

What exam hint can help solve this Mathematics question?

\(a_2=4+1+1=6\) और \(a_3=6+\frac{6}{4}+2=\frac{19}{2}\) है। भिन्नों को अंत तक ठीक रखें।