यदि \(a_1=120\) और (a_{n+1}=a_n-\(n^2+n\)) है तो \(a_5\) क्या होगा?

If \(a_1=120\) and (a_{n+1}=a_n-\(n^2+n\)), what is \(a_5\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (80)

Step 1

Concept

The subtracted values are (2,6,12,20), so (120-40=80). Exam tip: list changing subtractions in order.

Step 2

Why this answer is correct

The correct answer is B. (80). The subtracted values are (2,6,12,20), so (120-40=80). Exam tip: list changing subtractions in order.

Step 3

Exam Tip

घटने वाले मान (2,6,12,20) हैं इसलिए (120-40=80) है। बदलते घटावों को क्रम से लिखें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=120\) और (a_{n+1}=a_n-\(n^2+n\)) है तो \(a_5\) क्या होगा? / If \(a_1=120\) and (a_{n+1}=a_n-\(n^2+n\)), what is \(a_5\)?

Correct Answer: B. (80). Explanation: घटने वाले मान (2,6,12,20) हैं इसलिए (120-40=80) है। बदलते घटावों को क्रम से लिखें। / The subtracted values are (2,6,12,20), so (120-40=80). Exam tip: list changing subtractions in order.

Which concept should I revise for this Mathematics MCQ?

The subtracted values are (2,6,12,20), so (120-40=80). Exam tip: list changing subtractions in order.

What exam hint can help solve this Mathematics question?

घटने वाले मान (2,6,12,20) हैं इसलिए (120-40=80) है। बदलते घटावों को क्रम से लिखें।