यदि \(a_1=1\), \(a_2=4\) और \(a_n=a_{n-1}+a_{n-2}+n\) है तो \(a_5\) क्या होगा?

If \(a_1=1\), \(a_2=4\), and \(a_n=a_{n-1}+a_{n-2}+n\), what is \(a_5\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (29)

Step 1

Concept

The terms are (1,4,8,16,29), so \(a_5=29\). Exam tip: add the current (n) with the previous two terms.

Step 2

Why this answer is correct

The correct answer is C. (29). The terms are (1,4,8,16,29), so \(a_5=29\). Exam tip: add the current (n) with the previous two terms.

Step 3

Exam Tip

पद (1,4,8,16,29) हैं इसलिए \(a_5=29\) है। पिछले दो पदों के साथ वर्तमान (n) जोड़ें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=1\), \(a_2=4\) और \(a_n=a_{n-1}+a_{n-2}+n\) है तो \(a_5\) क्या होगा? / If \(a_1=1\), \(a_2=4\), and \(a_n=a_{n-1}+a_{n-2}+n\), what is \(a_5\)?

Correct Answer: C. (29). Explanation: पद (1,4,8,16,29) हैं इसलिए \(a_5=29\) है। पिछले दो पदों के साथ वर्तमान (n) जोड़ें। / The terms are (1,4,8,16,29), so \(a_5=29\). Exam tip: add the current (n) with the previous two terms.

Which concept should I revise for this Mathematics MCQ?

The terms are (1,4,8,16,29), so \(a_5=29\). Exam tip: add the current (n) with the previous two terms.

What exam hint can help solve this Mathematics question?

पद (1,4,8,16,29) हैं इसलिए \(a_5=29\) है। पिछले दो पदों के साथ वर्तमान (n) जोड़ें।