किस मान पर (\(r^2-11r+30\)x+8) रेखीय बहुपद नहीं रहेगा?

For which value will (\(r^2-11r+30\)x+8) not remain a linear polynomial?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (r=5) या (r=6)(r=5) or (r=6)

Step 1

Concept

For it not to be linear, the coefficient of (x) must be (0). From \(r^2-11r+30=0\), (r=5) or (r=6).

Step 2

Why this answer is correct

The correct answer is A. (r=5) या (r=6) / (r=5) or (r=6). For it not to be linear, the coefficient of (x) must be (0). From \(r^2-11r+30=0\), (r=5) or (r=6).

Step 3

Exam Tip

रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(r^2-11r+30=0\) से (r=5) या (r=6) मिलता है।

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Mathematics Answer, Explanation and Revision Hints

किस मान पर (\(r^2-11r+30\)x+8) रेखीय बहुपद नहीं रहेगा? / For which value will (\(r^2-11r+30\)x+8) not remain a linear polynomial?

Correct Answer: A. (r=5) या (r=6) / (r=5) or (r=6). Explanation: रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(r^2-11r+30=0\) से (r=5) या (r=6) मिलता है। / For it not to be linear, the coefficient of (x) must be (0). From \(r^2-11r+30=0\), (r=5) or (r=6).

Which concept should I revise for this Mathematics MCQ?

For it not to be linear, the coefficient of (x) must be (0). From \(r^2-11r+30=0\), (r=5) or (r=6).

What exam hint can help solve this Mathematics question?

रेखीय न रहने के लिए (x) का गुणांक (0) होना चाहिए। \(r^2-11r+30=0\) से (r=5) या (r=6) मिलता है।