अनुक्रम \(2,5,10,17,26,\ldots\) का (n)वाँ पद \(a_n=n^2+1\) है। \(a_{12}-a_{10}\) का मान क्या है?
For the sequence \(2,5,10,17,26,\ldots\), the (n)th term is \(a_n=n^2+1\). What is the value of \(a_{12}-a_{10}\)?
Explanation opens after your attempt
C. (44)
Concept
\(a_{12}=145\) and \(a_{10}=101\), so the difference is (44). Exam tip: find both terms separately first.
Why this answer is correct
The correct answer is C. (44). \(a_{12}=145\) and \(a_{10}=101\), so the difference is (44). Exam tip: find both terms separately first.
Exam Tip
\(a_{12}=145\) और \(a_{10}=101\) इसलिए अंतर (44) है। पहले दोनों पद अलग-अलग निकालें।
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