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For a positive integer \(n\), which statement correctly identifies when \(\sqrt{n}\) is irrational?

Answer and explanation

Correct answer: If \(n\) is not a perfect square, then \(\sqrt{n}\) is irrational.

Option B is correct. If \(n\) is not a perfect square, its prime factorisation has at least one odd exponent, so \(\sqrt{n}\) cannot be rational. For example, \(12=2^2\times3\). Exam tip: first check whether the number is a perfect square.

Related tags

Number SystemsIrrational NumbersSquare RootsPerfect SquaresPrime FactorisationClass 9 MathematicsProof Of Irrationality Of Square Root 2 And Square Root 3Mathematics

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