वर्गमूल सर्पिल में \(\sqrt{288}\) को संख्या रेखा पर रखने से पहले कौन-सा अंतराल पहचानना सही होगा?
Before placing \(\sqrt{288}\) on the number line using a square root spiral, which interval is correct to identify?
Explanation opens after your attempt
B. \(16<\sqrt{288}<17\)
Concept
Because \(16^2<288<17^2\). Therefore \(\sqrt{288}\) lies between (16) and (17).
Why this answer is correct
The correct answer is B. \(16<\sqrt{288}<17\). Because \(16^2<288<17^2\). Therefore \(\sqrt{288}\) lies between (16) and (17).
Exam Tip
क्योंकि \(16^2<288<17^2\) है। इसलिए \(\sqrt{288}\) (16) और (17) के बीच होगा।
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