वर्गमूल सर्पिल में \(\sqrt{288}\) को संख्या रेखा पर रखने से पहले कौन-सा अंतराल पहचानना सही होगा?

Before placing \(\sqrt{288}\) on the number line using a square root spiral, which interval is correct to identify?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. \(16<\sqrt{288}<17\)

Step 1

Concept

Because \(16^2<288<17^2\). Therefore \(\sqrt{288}\) lies between (16) and (17).

Step 2

Why this answer is correct

The correct answer is B. \(16<\sqrt{288}<17\). Because \(16^2<288<17^2\). Therefore \(\sqrt{288}\) lies between (16) and (17).

Step 3

Exam Tip

क्योंकि \(16^2<288<17^2\) है। इसलिए \(\sqrt{288}\) (16) और (17) के बीच होगा।

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वर्गमूल सर्पिल में \(\sqrt{288}\) को संख्या रेखा पर रखने से पहले कौन-सा अंतराल पहचानना सही होगा? / Before placing \(\sqrt{288}\) on the number line using a square root spiral, which interval is correct to identify?

Correct Answer: B. \(16<\sqrt{288}<17\). Explanation: क्योंकि \(16^2<288<17^2\) है। इसलिए \(\sqrt{288}\) (16) और (17) के बीच होगा। / Because \(16^2<288<17^2\). Therefore \(\sqrt{288}\) lies between (16) and (17).

Which concept should I revise for this Mathematics MCQ?

Because \(16^2<288<17^2\). Therefore \(\sqrt{288}\) lies between (16) and (17).

What exam hint can help solve this Mathematics question?

क्योंकि \(16^2<288<17^2\) है। इसलिए \(\sqrt{288}\) (16) और (17) के बीच होगा।