\(9r^2s-4rs+rs-5r^2s\) को सरल करने पर \(r^2s\) का गुणांक क्या होगा?
After simplifying \(9r^2s-4rs+rs-5r^2s\), what will be the coefficient of \(r^2s\)?
Explanation opens after your attempt
B. (4)
Concept
The \(r^2s\) terms are \(9r^2s\) and \(-5r^2s\). Their sum is \(4r^2s\).
Why this answer is correct
The correct answer is B. (4). The \(r^2s\) terms are \(9r^2s\) and \(-5r^2s\). Their sum is \(4r^2s\).
Exam Tip
\(r^2s\) वाले पद \(9r^2s\) और \(-5r^2s\) हैं। उनका योग \(4r^2s\) है।
Login to save your score, XP, coins and progress.
