वर्गमूल सर्पिल में \(\sqrt{2}\) बनाने के बाद \(\sqrt{3}\) बनाने के लिए कौन-सा निर्माण सही है?
After constructing \(\sqrt{2}\), which construction is correct to make \(\sqrt{3}\) in a square root spiral?
Explanation opens after your attempt
Correct Answer
A. \(\sqrt{2}\) के सिरे पर (1) इकाई लंब खींचनाDraw a (1) unit perpendicular at the end of \(\sqrt{2}\)
Concept
\(\sqrt{2}\) becomes the previous hypotenuse side. A (1) unit perpendicular at its end gives the new hypotenuse \(\sqrt{3}\).
Why this answer is correct
The correct answer is A. \(\sqrt{2}\) के सिरे पर (1) इकाई लंब खींचना / Draw a (1) unit perpendicular at the end of \(\sqrt{2}\). \(\sqrt{2}\) becomes the previous hypotenuse side. A (1) unit perpendicular at its end gives the new hypotenuse \(\sqrt{3}\).
Exam Tip
\(\sqrt{2}\) पिछले कर्ण की भुजा बनती है। उसके सिरे पर (1) इकाई लंब से नया कर्ण \(\sqrt{3}\) मिलता है।
Login to save your score, XP, coins and progress.